(9x^4/x^2-16)/(x^7/(x-4)^2)

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Solution for (9x^4/x^2-16)/(x^7/(x-4)^2) equation: 


D( x )

(x-4)^2 = 0

(x^7)/((x-4)^2) = 0

x^2 = 0

(x-4)^2 = 0

(x-4)^2 = 0

x-4 = 0 // + 4

x = 4

(x^7)/((x-4)^2) = 0

(x^7)/((x-4)^2) = 0

1*x^7 = 0 // : 1

x^7 = 0

x = 0

x^2 = 0

x^2 = 0

1*x^2 = 0 // : 1

x^2 = 0

x = 0

x in (-oo:0) U (0:4) U (4:+oo)

((9*x^4)/(x^2)-16)/((x^7)/((x-4)^2)) = 0

((9*x^2-16)*(x-4)^2)/(x^7) = 0

( 9*x^2-16 )

9*x^2 = 16 // : 9

x^2 = 16/9

x^2 = 16/9 // ^ 1/2

abs(x) = 4/3

x = 4/3 or x = -4/3

( x-4 )

x-4 = 0 // + 4

x = 4

x in { 4} 

x in { 4/3, -4/3 }

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